98x^2+7x-100=0

Solution for 98x^2+7x-100=0 equation:

98x^2+7x-100=0

a = 98; b = 7; c = -100;
Δ = b2-4ac
Δ = 72-4·98·(-100)
Δ = 39249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{39249}=\sqrt{441*89}=\sqrt{441}*\sqrt{89}=21\sqrt{89}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-21\sqrt{89}}{2*98}=\frac{-7-21\sqrt{89}}{196}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+21\sqrt{89}}{2*98}=\frac{-7+21\sqrt{89}}{196}
$